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python | ||
README.md |
14
This was nice! Similar to the Lanterfish one. The naive way is to have a big string, but that becomes unfeasible quickly.
The solution was to keep track of the number of combinations available and at the end divide by 2 the counted elements. Rounding up so that the first and last element is not neglected as they are not doubled.
Solutions
- 2988
- 3572761917024