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solutions/2/README.md
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@ -5,13 +5,6 @@ Just some simple parsing.
The second one is similar, but we can be more efficient if we XOR the first and second position.
# 2
For the first we can simply count the occurrences and see if they are between the accepted values.
Just some simple parsing.
The second one is similar, but we can be more efficient if we XOR the first and second position.
<details>
<summary>Solutions</summary>
<ol>

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# 3
We can simply parse the forest as an array of strings.
The trees repeat infinitely to the right, this screams for a good mod.
This means: `char = row[x % len(row)]`. No complex logic needed
For the second one we simply automate the process and sum up the total.
We can simply encode the coordinates as a function of the index we are current at.
<details>
<summary>Solutions</summary>
<ol>
<li>252</li>
<li>57 * 252 * 64 * 66 * 43 = 2608962048</li>
</ol>
</details>

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from typing import Dict, List
from os.path import join, dirname
from functools import reduce
class Forest():
def __init__(self, text: str) -> None:
self.text = text.strip().split('\n')
@property
def height(self) -> int:
return len(self.text)
def is_tree_at(self, y: int, x: int) -> bool:
if y > self.height:
return False
row = self.text[y]
return row[x % len(row)] == '#'
data = join(dirname(__file__), 'data.txt')
with open(data) as f:
forest = Forest(f.read())
# 1
trees: int = 0
for y in range(forest.height):
is_tree: bool = forest.is_tree_at(y, y*3)
if is_tree:
trees += 1
print(f'Result Simple: {trees}')
# 2
all: Dict[str, int] = {
'11': 0,
'13': 0,
'15': 0,
'17': 0,
'21': 0,
}
for i in range(forest.height):
for key, value in all.items():
dy, dx = map(int, list(key))
y = i * dy
x = i * dx
if forest.is_tree_at(y, x):
all[key] += 1
total = reduce((lambda x, y: x * y), all.values())
print(f'Result Combined: {list(all.values())} = {total}')

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