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solutions/7/README.md
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solutions/7/README.md
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# 7
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This one was maybe the coolest yet! Fixed-point iteration and some recursion. Amazing :)
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For the first part we iterate as long as we don't find any enclosing bags anymore. This can build long chains.
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The second we recurse down the bag chain und sum it up recursively.
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<details>
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<summary>Solutions</summary>
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<ol>
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<li>164</li>
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<li>7872</li>
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</ol>
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</details>
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solutions/7/python/main.py
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solutions/7/python/main.py
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from os.path import join, dirname
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from typing import Dict, List, Set, Tuple
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import re
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TRules = Dict[str, Dict[str, int]]
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def split_trim(input: str, split: str) -> List[str]:
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return list(map(lambda s: s.strip(), input.split(split)))
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def extract_inner(input: str) -> Tuple[int, str]:
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parts = input.split(' ')
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amount = int(parts[0])
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color = ' '.join(parts[1:-1])
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return amount, color
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def parse_rules(rules: str) -> TRules:
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d: TRules = {}
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for rule in rules.strip().split('\n'):
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outer, inner = split_trim(rule, 'contain')
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outer = re.sub(r'bags?', '', outer).strip()
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d[outer] = {
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color: amount
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for amount, color in [
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extract_inner(i)
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for i in split_trim(inner, ',')
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if 'no other bag' not in i # Also matches "bags"
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]
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}
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return d
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def find_enclosing_bags(rules: TRules, color: str) -> Set[str]:
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colors: Set[str] = set()
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stack: Set[str] = set([color])
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while len(stack):
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for item in list(stack):
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stack.remove(item)
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for contains, enclosing in rules.items():
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if item in enclosing:
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if contains not in colors:
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stack.add(contains)
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colors.add(contains)
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return colors
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def count_containing(rules: TRules, color: str) -> int:
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children = rules[color]
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if not children:
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return 0
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return sum([
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amount + amount * count_containing(rules, clr)
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for clr, amount in children.items()
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])
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data = join(dirname(__file__), '../data.txt')
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with open(data) as f:
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rules = parse_rules(f.read())
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color = 'shiny gold'
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first = len(find_enclosing_bags(rules, color))
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print(f'We can pack the {color} into {first} bags')
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second = count_containing(rules, color)
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print(f'We need to put {second} bags into {color}')
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