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Here are my solutions for the advent of code 2020 🎄🎅
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Here are my solutions for the advent of code 2020 🎄🎅
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Note that the exact solutions are different for some people.
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`/solutions/:day/*`
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`/solutions/:day/*`
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14
solutions/4/README.md
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solutions/4/README.md
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# 4
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This one was a lot of parsing, but nothing regexp can't do.
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The first is quite straight forward, just check that all but `cid` are present.
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The second was a bit of validation for each field, but again some simple regexp and number checking and the job is done 🙂
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<details>
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<summary>Solutions</summary>
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<ol>
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<li>206</li>
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<li>123</li>
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</ol>
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</details>
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52
solutions/4/main.py
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52
solutions/4/main.py
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from os.path import join, dirname
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import re
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def validate_chunk(chunk, extended=False):
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parts = re.split(' |\n', chunk.strip())
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password = dict(map(lambda p: p.split(":"), parts))
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required = ['byr', 'iyr', 'eyr', 'hgt', 'hcl', 'ecl', 'pid']
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if not all(item in password.keys() for item in required):
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return False
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if not extended:
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return True
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if not 1920 <= int(password['byr']) <= 2002:
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return False
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if not 2010 <= int(password['iyr']) <= 2020:
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return False
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if not 2020 <= int(password['eyr']) <= 2030:
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return False
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tmp = password['hgt']
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hgt = int(tmp[:-2])
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unit = tmp[-2:]
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if not unit in ['cm', 'in']:
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return False
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if unit == 'cm' and not 150 <= hgt <= 193:
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return False
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if unit == 'in' and not 59 <= hgt <= 76:
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return False
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if not re.match(r'^#[\dabcdef]{6}$', password['hcl']):
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return False
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if not re.match(r'^\d{9}$', password['pid']):
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return False
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if password['ecl'] not in ['amb', 'blu', 'brn', 'gry', 'grn', 'hzl', 'oth']:
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return False
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return True
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data = join(dirname(__file__), 'data.txt')
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with open(data) as f:
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chunks = re.split('\n\n+', f.read().strip())
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total_simple = 0
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total_extended = 0
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for chunk in chunks:
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total_simple += int(validate_chunk(chunk))
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total_extended += int(validate_chunk(chunk, extended=True))
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print(f'Simple Validation:\t{total_simple}')
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print(f'Extended Validation:\t{total_extended}')
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